Problem Statement
A rocket ejects gas at speed u relative to itself. Starting from rest, find the speed after ejecting mass Δm (initial mass m₀).
Given Information
- Exhaust speed: u relative to rocket
- Initial mass m₀
- Final mass m₀ − Δm
Physical Concepts & Formulas
$$v=u\ln\frac{m_0}{m}$$
Step-by-Step Solution
Step 1: Tsiolkovsky equation: v = u ln(m₀/m_f).
Step 2: m_f = m₀ − Δm.
Step 3: v = u ln(m₀/(m₀−Δm)) ≈ u(Δm/m₀) for small Δm.
Worked Calculation
v = u ln[m₀/(m₀−Δm)]
Answer
$$\boxed{v=u\ln\frac{m_0}{m_0-\Delta m}}$$
Physical Interpretation
The rocket equation shows that speed gain requires exponential fuel mass. This is why chemical rockets must carry so much propellant for orbital missions.
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