Problem Statement
A body of mass m at rest explodes into two parts of masses m₁ and m₂. The explosion releases energy E. Find the velocities of each part.
Given Information
- Mass m = m₁ + m₂ at rest
- Explosion energy E
Physical Concepts & Formulas
$$m_1v_1=m_2v_2,\quad \tfrac{1}{2}m_1v_1^2+\tfrac{1}{2}m_2v_2^2=E$$
Step-by-Step Solution
Step 1: Momentum: m₁v₁ = m₂v₂ → v₁/v₂ = m₂/m₁.
Step 2: KE: ½m₁v₁² + ½m₂v₂² = E.
Step 3: v₁ = √(2Em₂/[m₁(m₁+m₂)]), v₂ = √(2Em₁/[m₂(m₁+m₂)]).
Worked Calculation
v₁ = √(2Em₂/[m₁m]) where m = m₁+m₂
Answer
$$\boxed{v_1=\sqrt{\frac{2Em_2}{m_1(m_1+m_2)}},\quad v_2=\sqrt{\frac{2Em_1}{m_2(m_1+m_2)}}}$$
Physical Interpretation
The lighter fragment moves faster to conserve momentum. Total KE equals the explosion energy. Heavier fragments carry more momentum but less KE.
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