Problem Statement
A ball of mass m moving at speed v₀ hits a wall and bounces back with speed v₀ (perfectly elastic). Find the impulse delivered to the wall.
Given
m, v₀ before and after (reversed direction). Elastic bounce off wall.
Concepts & Formulas
Impulse = change in momentum of ball (in magnitude, wall receives equal and opposite).
Step-by-Step Solution
Step 1: Initial momentum: +mv₀ (toward wall).
Step 2: Final momentum: −mv₀ (away from wall).
Step 3: Δp_ball = −mv₀ − mv₀ = −2mv₀.
Step 4: Impulse on wall = +2mv₀.
Worked Calculation
J_wall = 2mv₀.
Boxed Answer
Impulse on wall = 2mv₀
Physical Interpretation
The impulse is twice the ball’s momentum — because the ball reverses direction, the wall must absorb the initial momentum and supply the return momentum.
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