Problem Statement
A force F = aî + bĵ is applied at point r = xî + yĵ. Find the torque about the origin and about point (x₀, y₀).
Given Information
- Force F = (a, b)
- Point of application r = (x, y)
Physical Concepts & Formulas
$$\boldsymbol{\tau}=\mathbf{r}\times\mathbf{F}$$
Step-by-Step Solution
Step 1: τ about origin = r × F = (xb − ya)k̂.
Step 2: Displacement from (x₀,y₀): Δr = (x−x₀)î + (y−y₀)ĵ.
Step 3: τ about (x₀,y₀) = [(x−x₀)b − (y−y₀)a]k̂.
Worked Calculation
τ_origin = (xb−ya)k̂
Answer
$$\boxed{\boldsymbol{\tau}=(xb-ya)\hat{k}\text{ about origin}}$$
Physical Interpretation
Torque depends on the choice of reference point. The cross product selects the component of force perpendicular to the moment arm.
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