Problem Statement
A particle of mass m moves in a circle of radius R with angular velocity ω. Find its angular momentum about the center and about a point on the circumference.
Given Information
- Mass m, radius R, angular velocity ω
Physical Concepts & Formulas
$$L=mvR=m\omega R^2$$
Step-by-Step Solution
Step 1: Speed v = ωR.
Step 2: L about center = mvR = mωR².
Step 3: L about circumference point (distance varies): average = mωR² + 0… actually max = 2mωR², min = 0, instantaneous varies.
Worked Calculation
L_center = mωR²
Answer
$$\boxed{L_{center}=m\omega R^2}$$
Physical Interpretation
About the center (perpendicular axis), angular momentum is constant for uniform circular motion. About a rim point, it oscillates because the moment arm changes.
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