HC Verma Chapter 45 Problem 6

Problem Statement

p-type semiconductor: N_A = 4e23 m-3, n_i = 1.5e16 m-3. Find hole and electron concentrations.

Key Concepts

p-type doping, mass action law

Relevant Formulas

n * p = n_i^2

Step-by-Step Solution

p = N_A = 4e23 m-3. n = n_i^2/p = (1.5e16)^2/4e23 = 2.25e32/4e23 = 5.625e8 m-3.

Final Answer

p = 4e23 m-3; n = 5.625e8 m-3

Tips and Tricks

Minority carriers drastically reduced by heavy doping.

Common Mistakes

Always use SI units. Check energy conservation accounts for all forms.