Chapter 34, Problem 24
Bar magnet dipole: axis field = 2 mu0 m/(4 pi r^3), equatorial field = mu0 m/(4 pi r^3). Axis is twice equatorial.
Chapter 34, Problem 24
Bar magnet dipole: axis field = 2 mu0 m/(4 pi r^3), equatorial field = mu0 m/(4 pi r^3). Axis is twice equatorial.
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