Problem Statement
A brass rod is 2.0 m long at 27°C. At what temperature will it be 2.002 m long? ($\alpha_{brass} = 2.0 \times 10^{-5}$ °C$^{-1}$)
Given Information
- All quantities, constants, and constraints stated in the problem above
- Physical constants used as needed (see Concepts section)
Physical Concepts & Formulas
This problem draws on fundamental physical principles. The key is to identify which conservation law or field equation governs the system, then apply it systematically. Dimensional analysis can always be used to verify that the final answer has the correct units. Working from first principles — rather than memorising formulas — builds deeper understanding and allows tackling novel problems.
- Identify the relevant physical law (Newton’s laws, conservation of energy/momentum, Maxwell’s equations, etc.)
- State the mathematical form of that law as it applies here
- Check dimensions at every step: both sides of an equation must have the same units
Step-by-Step Solution
Problem Statement
A brass rod is 2.0 m long at 27°C. At what temperature will it be 2.002 m long? ($\alpha_{brass} = 2.0 \times 10^{-5}$ °C$^{-1}$)
Given Information
- $L_0 = 2.0$ m at $T_1 = 27°C$
- $L = 2.002$ m
- $\alpha = 2.0 \times 10^{-5}$ °C$^{-1}$
Physical Concepts & Formulas
$$\Delta L = L_0 \alpha \Delta T \Rightarrow \Delta T = \frac{\Delta L}{L_0 \alpha}$$
Step-by-Step Solution
Step 1: Find the required expansion.
$$\Delta L = 2.002 – 2.0 = 0.002 \text{ m}$$
Step 2: Solve for $\Delta T$.
$$\Delta T = \frac{0.002}{2.0 \times 2.0 \times 10^{-5}} = \frac{0.002}{4.0 \times 10^{-5}}$$
Step 3: Compute and find $T_2$.
$$\Delta T = 50°C \Rightarrow T_2 = 27 + 50 = 77°C$$
Worked Calculation
$$\Delta T = \frac{0.002}{2.0 \times 2.0 \times 10^{-5}} = \frac{2 \times 10^{-3}}{4 \times 10^{-5}} = 50°C$$
$$T_2 = 27 + 50 = 77°C$$
Answer
$T_2 = 77°C$
Physical Interpretation
Heating the brass rod by 50°C produces the required 2 mm elongation. Brass has a relatively high expansion coefficient, making it useful in bimetallic strips for thermostats where large deflections per degree are needed.
Worked Calculation
Substituting all given numerical values with their units into the derived formula:
$$\text{Numerical result} = \text{given expression substituted with values}$$
Answer
$$\boxed{T_2 = 27 + 50 = 77°C}$$
Physical Interpretation
The answer should be checked for dimensional consistency and physical reasonableness: is the magnitude in the expected range for this type of problem? Does the answer change in the correct direction when parameters are varied (e.g., increasing mass should increase momentum, increasing distance should decrease field strength)? These sanity checks are as important as the calculation itself.
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