Problem Statement
A rocket in free space (no gravity) ejects gas at speed u = 3.0 km/s relative to rocket. Find the mass ratio m₀/m_f needed to reach v = 12 km/s.
Given Information
- Exhaust velocity u = 3.0 km/s
- Final velocity v = 12 km/s
Physical Concepts & Formulas
$$v=u\ln(m_0/m_f)\Rightarrow m_0/m_f=e^{v/u}$$
Step-by-Step Solution
Step 1: v/u = 12/3 = 4.
Step 2: m₀/m_f = e⁴ ≈ 54.6.
Step 3: About 98% of initial mass must be propellant.
Worked Calculation
m₀/m_f = e^4 ≈ 54.6
Answer
$$\boxed{m_0/m_f=e^{v/u}=e^4\approx 54.6}$$
Physical Interpretation
To reach 4 times exhaust velocity, you need 54× mass ratio. This exponential dependence makes high-Δv missions extremely fuel-intensive.
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