Category: HC Verma Part 1: Waves & Optics
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HC Verma Chapter 17 Problem 41 — YDSE intensity at center when one slit covered
Problem Statement In YDSE, if one slit is covered, what fraction of the maximum double-slit intensity is observed at the center? Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem draws on fundamental physical principles. The key is…
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HC Verma Chapter 17 Problem 38 — wavelength from fringe shift with slab
Problem Statement Solve the oscillation/wave problem: A glass slab ($n=1.5$, $t=0.1$ mm) causes a shift of 83 fringes in YDSE. Find wavelength. $\lambda=(n-1)t/$fringe shift Step 1: Shift $=(n-1)t/\lambda$; $83=(0.5\times0.1\times10^{-3})/\lambda$; $\lambda=0.5\times10^{-4}/83\approx6.02\times10^{-7}$ m $\approx602$ nm. $$\boxed{\lambda\approx602\text{ Given Information Mass $m$ and spring constant $k$ (or equivalent), or wave parameters Initial conditions (amplitude $A$, phase $\phi$) as given…
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HC Verma Chapter 17 Problem 39 — coherence length and line width
Problem Statement A spectral line has width $\Delta\lambda=0.01$ nm at $\lambda=500$ nm. Find the coherence length. Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem draws on fundamental physical principles. The key is to identify which conservation law…
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HC Verma Chapter 17 Problem 37 — refractive index from minimum slab thickness for shift
Problem Statement Solve the optics problem: A glass slab of thickness 1 mm in YDSE causes a shift equal to 10 fringes. $\lambda=600$ nm. Find refractive index. Fringe shift $=(n-1)t/\lambda\Rightarrow n=1+$(shift)$\lambda/t$ Step 1: Fringe shift $=(n-1)t/\lambda$; $10=(n-1)\times10^{-3}/(600\times10^{-9})$. Step 2: $(n-1)=10\times600\times10^ Given Information Refractive index $n$ or focal length $f$ as given Object distance $u$ (negative…
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HC Verma Chapter 17 Problem 36 — visibility of fringes
Problem Statement Two coherent sources have intensities $I_1=4I$ and $I_2=I$. Find fringe visibility. Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem draws on fundamental physical principles. The key is to identify which conservation law or field equation…
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HC Verma Chapter 17 Problem 34 — condition for white light to show no color
Problem Statement A thin film in air ($n=1.5$) of thickness 400 nm. For which visible wavelength is there no reflection (destructive)? Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem draws on fundamental physical principles. The key is…
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HC Verma Chapter 17 Problem 35 — YDSE with source shifted off axis
Problem Statement In YDSE, the source is shifted by 1 mm off axis. How does the fringe pattern change? ($S_1S_2=d=1$ mm, $D_s=1$ m from slits, screen at $D=1$ m.) Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem…
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HC Verma Chapter 17 Problem 32 — thin film wedge dark fringes
Problem Statement A wedge-shaped film has an angle $\theta=0.01$ rad. Light of 600 nm is incident normally. Find the fringe spacing. Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem draws on fundamental physical principles. The key is…
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HC Verma Chapter 17 Problem 33 — Newton rings — radius of curvature from ring spacing
Problem Statement Solve the Newton’s Laws / mechanics problem: In Newton’s rings, radii of 5th and 15th dark rings are 3.0 mm and 5.2 mm respectively. $\lambda=589$ nm. Find radius of curvature. $R=(r_m^2-r_n^2)/[(m-n)\lambda]$ from Newton’s ring measurements Step 1: $r_n^2=n\lambda R$; $r_{15}^2-r_5^2=(15-5)\lambda R$. Step 2: $R=(r_{15}^2-r_5^2)/(10\lambda)=( Given Information Mass(es), forces, angles, and coefficients of friction…
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HC Verma Chapter 17 Problem 31 — intensity at a point in YDSE given path difference
Problem Statement YDSE with equal amplitude sources, $\lambda=500$ nm. Find intensity at a point where path difference is 125 nm (express as fraction of maximum). Given Information All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) Physical Concepts & Formulas This problem draws on fundamental physical…