Category: HC Verma Part 2: Modern Physics
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HC Verma Chapter 42 Problem 10 — Number of Photons per Second from a Source
Problem Statement Solve the quantum/modern physics problem: Solve the quantum/modern physics problem: A 100 W sodium vapour lamp emits monochromatic light at $\lambda = 589$ nm. Assuming 10% efficiency (electrical to light), find the number of photons emitted per second. $N = P_{light}/(hf) = P_{light}\lambda/(hc)$ Step 1: Light output power: $P_{light} = 0. Given Information…
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HC Verma Chapter 42 Problem 9 — Effect of Stopping Potential on Photocurrent
Problem Statement Analyze the circuit: Solve the quantum/modern physics problem: In a photoelectric experiment, the stopping potential for $\lambda = 300$ nm light is $V_1 = 1.85$ V. If the wavelength is changed to $\lambda = 400$ nm, find the new stopping potential. (Work function can be calculated from first measurement.) $eV_s = hc/\l Given…
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HC Verma Chapter 42 Problem 8 — Maximum Speed of Photoelectrons
Problem Statement Solve the kinematics problem: Ultraviolet light of wavelength $\lambda = 180$ nm is incident on a lithium surface (work function $\phi = 2.5$ eV). Find the maximum speed of emitted electrons. $KE_{max} = hc/\lambda – \phi = \frac{1}{2}m_e v_{max}^2$ Step 1: Photon energy: $E_{ph} = 1240/180 = 6.89$ eV Step 2: $KE_{max} =…
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HC Verma Chapter 42 Problem 7 — Photocurrent and Intensity
Problem Statement Analyze the circuit: Analyze the circuit: A photocell uses a surface of work function $\phi = 1.9$ eV and is illuminated by light of wavelength $\lambda = 400$ nm and intensity $I = 2$ W/m². The cell has area $A = 1$ cm$^2$. If quantum efficiency (fraction of photons causing emission) is $\eta…
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HC Verma Chapter 42 Problem 6 — de Broglie Wavelength of Photoelectron
Problem Statement Solve the oscillation/wave problem: Solve the quantum/modern physics problem: Light of wavelength 200 nm falls on an aluminium surface (work function $\phi = 4.2$ eV). Find the de Broglie wavelength of the fastest emitted photoelectrons. $KE_{max} = hc/\lambda – \phi$ $\lambda_{dB} = h/p = h/\sqrt{2m_eKE}$ Step 1: Photon energy: $E_{p Given Information Mass…
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HC Verma Chapter 42 Problem 5 — Work Function from Threshold Wavelength
Problem Statement Solve the quantum/modern physics problem: Solve the oscillation/wave problem: The photoelectric threshold wavelength for a metal is $\lambda_0 = 540$ nm. Find the work function of the metal. $\phi = hc/\lambda_0$ $hc = 1240$ eV·nm Step 1: $$\phi = \frac{hc}{\lambda_0} = \frac{1240\text{ eV·nm}}{540\text{ nm}} = 2.30\text{ eV}$$ $$\boxed{\ph Given Information $\phi = \frac{hc}{\lambda_0}…
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HC Verma Chapter 42 Problem 4 — Planck’s Constant from Photoelectric Data
Problem Statement Solve the quantum/modern physics problem: Solve the quantum/modern physics problem: In a photoelectric experiment, the stopping potential is $V_s = 1.0$ V for light of $\lambda_1 = 250$ nm and $V_s = 0.5$ V for $\lambda_2 = 350$ nm. Find Planck’s constant $h$ and the work function $\phi$. $eV_s = hc/\lambda – \phi$;…
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HC Verma Chapter 42 Problem 3 — Stopping Potential
Problem Statement Solve the quantum/modern physics problem: When light of frequency $f = 8\times10^{14}$ Hz falls on a metal surface of work function $\phi = 1.6$ eV, find the stopping potential. All quantities, constants, and constraints stated in the problem above Physical constants used as needed (see Concepts section) This problem draws on fundamental ph…
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HC Verma Chapter 42 Problem 2 — Maximum Kinetic Energy of Photoelectrons
Problem Statement Solve the work-energy problem: Solve the work-energy problem: Light of wavelength $\lambda = 300$ nm falls on a metal with work function $\phi = 2.0$ eV. Find the maximum kinetic energy of emitted photoelectrons. Einstein’s photoelectric equation: $KE_{max} = hf – \phi = hc/\lambda – \phi$ Step 1: Photon energy: $$E_{ph} = \frac{…
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HC Verma Chapter 42 Problem 1 — Threshold Frequency for Photoelectric Effect
Problem Statement Solve the quantum/modern physics problem: Solve the quantum/modern physics problem: The work function of sodium is $\phi = 2.3$ eV. Find the threshold frequency $f_0$ below which no photoelectric emission occurs. $\phi = hf_0 \Rightarrow f_0 = \phi/h$ $h = 6.626\times10^{-34}$ J·s $= 4.136\times10^{-15}$ eV·s Step 1: $$f_0 = \frac{\phi}{h} Given Information See…