Author: dexter
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HC Verma Chapter 25 Problem 37
Problem Statement How much heat is released when 5 g of steam at 100°C is converted to ice at 0°C? L_v = 2.27×10⁶ J/kg, c_water = 4200 J/(kg·K), L_f = 3.36×10⁵ J/kg. Given Information m = 5 g = 0.005 kg L_v = 2.27×10⁶ J/kg c_w = 4200 J/(kg·K) L_f = 3.36×10⁵ J/kg Physical Concepts…
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HC Verma Chapter 12 Problem 6
Given / Data HC Verma Chapter 12 Problem 6. Refer to your copy of Concepts of Physics Part 1 by H.C. Verma for the complete problem statement. Concept / Formula SHM restoring force F=-kx. x=A sin(omega*t+phi). omega=sqrt(k/m). T=2pi/omega. E=0.5kA^2=constant. Step-by-step Solution General approach for Chapter 12 Problem 6:Step 1: Verify F proportional to -x.Step 2:…
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HC Verma Chapter 12 Problem 6
Given / Data HC Verma Chapter 12 Problem 6. Refer to your copy of Concepts of Physics Part 1 by H.C. Verma for the complete problem statement. Concept / Formula SHM restoring force F=-kx. x=A sin(omega*t+phi). omega=sqrt(k/m). T=2pi/omega. E=0.5kA^2=constant. Step-by-step Solution General approach for Chapter 12 Problem 6:Step 1: Verify F proportional to -x.Step 2:…
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HC Verma Chapter 38 Problem 45
Problem Statement A circular coil of $N = 70$ turns and radius $R = 5\,\text{cm}$ is in a field that changes by $\Delta B = 1.0\,\text{T}$ in $\Delta t = 0.1\,\text{s}$. The plane is perpendicular to the field. Find the induced emf. Given Information $N = 70$ turns $R = 0.05\,\text{m}$, area $A = \pi…
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HC Verma Chapter 25 Problem 36
Problem Find Cv of a mixture of 1 mole Ne and 1 mole Cl2 (treat Cl2 as diatomic rigid). Key Concepts Cv_mix=(n1 Cv1+n2 Cv2)/(n1+n2); Cv(Ne)=3R/2; Cv(Cl2)=5R/2 Solution Cv_mix=(1x3R/2+1x5R/2)/2=(3R/2+5R/2)/2=8R/4=2R=16.63 J/mol K. Answer Cv_mix = 2R = 16.63 J/mol K Concept Check Average of monatomic and diatomic Cv. Common Mistakes Mixing Cp values instead of Cv. Practice…
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HC Verma Chapter 12 Problem 5
Given / Data HC Verma Chapter 12 Problem 5. Refer to your copy of Concepts of Physics Part 1 by H.C. Verma for the complete problem statement. Concept / Formula SHM restoring force F=-kx. x=A sin(omega*t+phi). omega=sqrt(k/m). T=2pi/omega. E=0.5kA^2=constant. Step-by-step Solution General approach for Chapter 12 Problem 5:Step 1: Verify F proportional to -x.Step 2:…
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HC Verma Chapter 12 Problem 5
Given / Data HC Verma Chapter 12 Problem 5. Refer to your copy of Concepts of Physics Part 1 by H.C. Verma for the complete problem statement. Concept / Formula SHM restoring force F=-kx. x=A sin(omega*t+phi). omega=sqrt(k/m). T=2pi/omega. E=0.5kA^2=constant. Step-by-step Solution General approach for Chapter 12 Problem 5:Step 1: Verify F proportional to -x.Step 2:…
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HC Verma Chapter 38 Problem 44
Problem Statement A circular coil of $N = 60$ turns and radius $R = 25\,\text{cm}$ is in a field that changes by $\Delta B = 0.5\,\text{T}$ in $\Delta t = 0.5\,\text{s}$. The plane is perpendicular to the field. Find the induced emf. Given Information $N = 60$ turns $R = 0.25\,\text{m}$, area $A = \pi…
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HC Verma Chapter 25 Problem 35
Problem A gas absorbs 400 J at constant volume. Then 200 J at constant pressure. Find total change in internal energy. Key Concepts Const V: dU1=Q1=400 J. Const P: dU2=Q2-W=Q2-nR dT. Solution dU1=400 J. For const P process: Q2=200 J, W=nR dT=dU2-dU2… Actually dU2=nCv dT and W=nR dT, Q=nCp dT. Fraction going to U: dU2=Q2xCv/Cp=200x(f/2)/((f/2)+1).…
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HC Verma Chapter 12 Problem 4
Given / Data HC Verma Chapter 12 Problem 4. Refer to your copy of Concepts of Physics Part 1 by H.C. Verma for the complete problem statement. Concept / Formula SHM restoring force F=-kx. x=A sin(omega*t+phi). omega=sqrt(k/m). T=2pi/omega. E=0.5kA^2=constant. Step-by-step Solution General approach for Chapter 12 Problem 4:Step 1: Verify F proportional to -x.Step 2:…