Problem Statement
A cylinder of mass m rolls without slipping on a plank that accelerates at a₀. Find the acceleration of the cylinder’s center.
Given Information
- Plank acceleration a₀
- Cylinder: mass m, radius R, I = ½mR²
Physical Concepts & Formulas
Rolling constraint on moving surface: a_cyl − a_plank = −Rα (no slip condition)
Step-by-Step Solution
Step 1: Friction f on cylinder: ma_cyl = f.
Step 2: Rotation: (½mR²)α = fR → α = f/(½mR) = 2f/(mR).
Step 3: No-slip: a_plank − a_cyl = Rα = 2f/m = 2a_cyl → a₀ − a_cyl = 2a_cyl → a_cyl = a₀/3.
Worked Calculation
a_cylinder = a₀/3
Answer
$$\boxed{a_{cylinder}=\frac{a_0}{3}}$$
Physical Interpretation
The cylinder lags behind the plank. In the plank’s frame, it appears to roll backward at 2a₀/3. Static friction provides the coupling between translational and rotational motion.
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