Problem Statement
A stone is thrown at angle θ with speed v₀. Find the angular momentum about the launch point as a function of time.
Given Information
- Launch angle θ, speed v₀
- Origin at launch point
Physical Concepts & Formulas
$$L_z=m(xv_y-yv_x)$$
Step-by-Step Solution
Step 1: x = v₀cosθ·t, y = v₀sinθ·t − ½gt².
Step 2: vₓ = v₀cosθ, vᵧ = v₀sinθ − gt.
Step 3: L = m(xvᵧ − yvₓ) = m·v₀cosθ·t·(v₀sinθ−gt) − m·(v₀sinθ·t−½gt²)·v₀cosθ = ½mgv₀t²cosθ.
Worked Calculation
L = ½mgv₀t²cosθ
Answer
$$\boxed{L=\frac{1}{2}mgv_0t^2\cos\theta}$$
Physical Interpretation
Angular momentum grows as t² because gravity exerts a torque mgx = mg·v₀cosθ·t that grows linearly with time, causing L to increase as t².
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