Problem Statement
A rocket launches vertically from Earth surface with exhaust speed u and mass ejection rate β = dm/dt. Find velocity as a function of mass.
Given Information
- Exhaust speed u
- Mass ejection rate β
- Gravity g
Physical Concepts & Formulas
$$m\frac{dv}{dt}=\beta u – mg,\quad \frac{dm}{dt}=-\beta$$
Step-by-Step Solution
Step 1: With dm/dt = −β: m dv = −u dm − mg dt.
Step 2: t = (m₀−m)/β, so mg dt = g(m₀−m)dm/(−βm)·(−β)… integrating.
Step 3: v = u ln(m₀/m) − g(m₀−m)/β.
Worked Calculation
v = u ln(m₀/m) − g(m₀−m)/β
Answer
$$\boxed{v=u\ln\frac{m_0}{m}-\frac{g(m_0-m)}{\beta}}$$
Physical Interpretation
Gravity subtracts from the Tsiolkovsky velocity. Fast burn (large β) minimizes gravity losses. This is why rocket engines are run at full throttle during launch.
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