HC Verma Chapter 4 Problem 5 — Normal force on inclined plane

Problem Statement

Solve the Newton’s Laws / mechanics problem: Solve the Newton’s Laws / mechanics problem: A block of mass 4 kg is placed on a smooth incline of 30°. Find the normal force from the incline and the acceleration of the block along the incline. ($g = 10$ m/s²) $N = mg\cos\theta$; $a = g\sin\theta$ Step 1: $N = mg\cos 30° = 4 \times 10 \times (\sqr

Given Information

  • See problem statement for all given quantities.

Physical Concepts & Formulas

Friction is a contact force opposing relative motion (kinetic friction) or impending motion (static friction). On an inclined plane, the weight component along the slope is $mg\sin\theta$ and the normal force is $N = mg\cos\theta$, giving maximum static friction $f_{s,\max} = \mu_s mg\cos\theta$. The condition for sliding is $\tan\theta > \mu_s$.

  • $f = \mu N$ — kinetic friction force
  • $N = mg\cos\theta$ — normal force on incline
  • $mg\sin\theta – \mu mg\cos\theta = ma$ — Newton’s 2nd law along incline
  • $\tan\theta_c = \mu_s$ — critical angle for sliding

Step-by-Step Solution

Step 1 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 2 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 3 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Worked Calculation

Full substitution shown in the steps above.

Answer

$$\boxed{a = \dfrac{(m_2-m_1)g}{m_1+m_2}}$$

Physical Interpretation

The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.


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