HC Verma Chapter 15 Problem 43 — wave speed from string fundamental

Problem Statement

Solve the oscillation/wave problem: Solve the oscillation/wave problem: Guitar string: length 62.5 cm, fundamental 250 Hz. Wave speed? $v=2Lf_1$ Step 1: $v=2Lf_1=2\times0.625\times250=312.5$ m/s. $$\boxed{v=312.5\text{ m/s}}$$ Mass $m$ and spring constant $k$ (or equivalent), or wave parameters Initial conditions (amplitude $A$, phase

Given Information

  • $v=2Lf$
  • $v=2Lf$
  • $\boxed{v=312.5\text{ m/s}$

Physical Concepts & Formulas

This problem applies fundamental physics principles to the scenario described. The solution requires identifying the relevant conservation laws and equations of motion, then solving systematically with careful attention to units and sign conventions.

  • See the step-by-step solution for the specific equations applied.
  • All quantities are in SI units unless otherwise stated.

Step-by-Step Solution

Step 1 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 2 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 3 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Worked Calculation

$$\boxed{v=312.5\text{ m/s}}$$

$$T = 2\pi\sqrt{\frac{m}{k}}\quad,\quad v_{\max} = A\omega_0 = A\sqrt{\frac{k}{m}}$$

$$\boxed{T = 2\pi\sqrt{m/k}}$$

Answer

$$\boxed{v=312.5\text{ m/s}}$$

Physical Interpretation

The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.


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