HC Verma Chapter 3 Problem 37 — Velocity of one particle relative to another

Problem Statement

Solve the kinematics problem: Particle A has velocity $10\hat{i}$ m/s and particle B has velocity $10\hat{j}$ m/s. Find the velocity of A relative to B. $\vec{v}_{AB} = \vec{v}_A – \vec{v}_B$ Step 1: $\vec{v}_{AB} = 10\hat{i} – 10\hat{j}$ m/s. Step 2: $|\vec{v}_{AB}| = \sqrt{100+100} = 10\sqrt{2} \approx 14.1$ m/s at 45° below t

Given Information

  • See problem statement for all given quantities.

Physical Concepts & Formulas

Relative velocity $\mathbf{v}_{AB} = \mathbf{v}_A – \mathbf{v}_B$ is the velocity of A as seen from B’s reference frame. For river-crossing problems, the boat’s velocity relative to ground = boat velocity relative to water + water velocity. The angle for minimum crossing time differs from the angle for minimum drift.

  • $\mathbf{v}_{A/B} = \mathbf{v}_A – \mathbf{v}_B$
  • River crossing: $\mathbf{v}_{\text{ground}} = \mathbf{v}_{\text{boat/water}} + \mathbf{v}_{\text{river}}$
  • Minimum time: boat aims perpendicular to river bank
  • Minimum drift: $\sin\phi = v_{\text{boat}}/v_{\text{river}}$ (if river faster)

Step-by-Step Solution

Step 1 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 2 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 3 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Worked Calculation

$$R = \frac{u^2\sin 2\theta}{g} = \frac{400\times\sin 60°}{9.8} = \frac{400\times0.866}{9.8} = \frac{346.4}{9.8} \approx 35.3\,\text{m}$$

$$H = \frac{u^2\sin^2\theta}{2g} = \frac{400\times0.25}{19.6} = \frac{100}{19.6} \approx 5.1\,\text{m}$$

$$\boxed{R = \dfrac{u^2\sin 2\theta}{g},\quad H = \dfrac{u^2\sin^2\theta}{2g}}$$

Answer

$$\boxed{R = \dfrac{u^2\sin 2\theta}{g},\quad H = \dfrac{u^2\sin^2\theta}{2g}}$$

Physical Interpretation

The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.


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