HC Verma Chapter 29 Problem 50 – Flux Through a Face When Charge is at Corner

Problem Statement

A charge $q$ is placed at a corner of a cube. Find the flux through each of the three faces adjacent to the corner, and each of the three faces not adjacent.

Given Information

  • See problem statement for all given quantities.

Physical Concepts & Formulas

This problem applies fundamental physics principles to the scenario described. The solution requires identifying the relevant conservation laws and equations of motion, then solving systematically with careful attention to units and sign conventions.

  • See the step-by-step solution for the specific equations applied.
  • All quantities are in SI units unless otherwise stated.

Step-by-Step Solution

Step 1 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 2 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Step 3 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Worked Calculation

$$\Phi_{each\ opposite} = \frac{q}{8\varepsilon_0\times3}\cdot3 \div 3 = \frac{q}{24\varepsilon_0}$$

$$\boxed{\Phi_{adjacent} = 0,\quad \Phi_{opposite} = \frac{q}{24\varepsilon_0} \text{ per face}}$$

$$\text{Numerical result} = \text{given expression substituted with values}$$

Answer

$$\boxed{\Phi_{adjacent} = 0,\quad \Phi_{opposite} = \frac{q}{24\varepsilon_0} \text{ per face}}$$

Physical Interpretation

The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.


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