Problem 5.120 — Luminous Efficacy

Problem Statement

A light source consumes $P = 60$ W of electrical power and produces a luminous flux of $\Phi = 840$ lm. Find the luminous efficacy and compare with the theoretical maximum ($683$ lm/W for 555 nm).

Given Information

  • See problem statement for all given quantities.

Physical Concepts & Formulas

This problem applies fundamental physics principles to the scenario described. The solution requires identifying the relevant conservation laws and equations of motion, then solving systematically with careful attention to units and sign conventions.

  • See the step-by-step solution for the specific equations applied.
  • All quantities are in SI units unless otherwise stated.

Step-by-Step Solution

Step 1 — Identify given quantities and set up the problem: $$\eta = \frac{\Phi}{P} = \frac{840}{60} = \boxed{14\text{ lm/W}}$$

Step 2 — Apply the relevant physical law or equation: This is about $14/683 = 2.0\%$ of the theoretical maximum — typical of an incandescent lamp.

Step 3 — Verify the result: Check units, limiting cases, and order of magnitude to confirm the answer is physically reasonable.

Worked Calculation

$$\eta = \frac{\Phi}{P} = \frac{840}{60} = \boxed{14\text{ lm/W}}$$

$$\text{Numerical result} = \text{given expression substituted with values}$$

$$\boxed{\eta = \frac{\Phi}{P} = \frac{840}{60} = \boxed{14\text{ lm/W}}}$$

$$\eta = \frac{\Phi}{P} = \frac{840}{60} = \boxed{14\text{ lm/W}}$$

This is about $14/683 = 2.0\%$ of the theoretical maximum — typical of an incandescent lamp.

Answer

$$\eta = \frac{\Phi}{P} = \frac{840}{60} = \boxed{14\text{ lm/W}}$$

Physical Interpretation

The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.


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