Problem Statement
A grating has slit width $b = 0.10$ mm and slit period $d = 0.30$ mm. Which orders of the principal maxima are missing?
Given Information
- See problem statement for all given quantities.
Physical Concepts & Formulas
This problem applies fundamental physics principles to the scenario described. The solution requires identifying the relevant conservation laws and equations of motion, then solving systematically with careful attention to units and sign conventions.
- See the step-by-step solution for the specific equations applied.
- All quantities are in SI units unless otherwise stated.
Step-by-Step Solution
Step 1 — Identify given quantities and set up the problem: Orders missing when a principal maximum coincides with a diffraction minimum: $m = d/b \times p$ for integer $p$.
Step 2 — Apply the relevant physical law or equation: $$\frac{d}{b} = \frac{0.30}{0.10} = 3$$
Step 3 — Solve algebraically for the unknown: Missing orders: $m = 3, 6, 9, \ldots$ — every multiple of $\boxed{3}$.
Worked Calculation
$$\frac{d}{b} = \frac{0.30}{0.10} = 3$$
$$\text{Numerical result} = \text{given expression substituted with values}$$
$$\boxed{\frac{d}{b} = \frac{0.30}{0.10} = 3}$$
Orders missing when a principal maximum coincides with a diffraction minimum: $m = d/b \times p$ for integer $p$.
$$\frac{d}{b} = \frac{0.30}{0.10} = 3$$
Missing orders: $m = 3, 6, 9, \ldots$ — every multiple of $\boxed{3}$.
Answer
$$\boxed{\frac{d}{b} = \frac{0.30}{0.10} = 3}$$
Physical Interpretation
The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.
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