Problem Statement
A thin glass plate ($n = 1.5$) of uniform thickness $t = 300$ nm is illuminated with white light at normal incidence. What colors are seen in reflection?
Given Information
- See problem statement for all given quantities.
Physical Concepts & Formulas
This problem applies fundamental physics principles to the scenario described. The solution requires identifying the relevant conservation laws and equations of motion, then solving systematically with careful attention to units and sign conventions.
- See the step-by-step solution for the specific equations applied.
- All quantities are in SI units unless otherwise stated.
Step-by-Step Solution
Step 1 — Identify given quantities and set up the problem: Constructive reflection: $\lambda = \frac{2nt}{m+1/2} = \frac{2\times1.5\times300}{m+0.5} = \frac{900}{m+0.5}$ nm.
Step 2 — Apply the relevant physical law or equation:
- $m=0$: $\lambda=1800$ nm (IR)
- $m=1$: $\lambda=600$ nm (orange-yellow, visible)
- $m=2$: $\lambda=360$ nm (near UV)
Step 3 — Solve algebraically for the unknown: The plate appears $\boxed{\text{orange-yellow}}$ in reflected light.
Worked Calculation
$$\text{Numerical result} = \text{given expression substituted with values}$$
$$\boxed{\boxed{\text{orange-yellow}}}$$
Constructive reflection: $\lambda = \frac{2nt}{m+1/2} = \frac{2\times1.5\times300}{m+0.5} = \frac{900}{m+0.5}$ nm.
- $m=0$: $\lambda=1800$ nm (IR)
- $m=1$: $\lambda=600$ nm (orange-yellow, visible)
- $m=2$: $\lambda=360$ nm (near UV)
The plate appears $\boxed{\text{orange-yellow}}$ in reflected light.
Answer
$$\boxed{\boxed{\text{orange-yellow}}}$$
Physical Interpretation
The numerical answer is physically reasonable — matching expected orders of magnitude and dimensional analysis. The result confirms the theoretical prediction and provides quantitative insight into the system’s behaviour.
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