Problem Statement
Solve the fluid mechanics problem: A sound wave in air has pressure amplitude $p_0=1.0$ Pa. Find displacement amplitude. Given: $v=330$ m/s, $\rho=1.29$ kg/m$^3$, $f=1000$ Hz. $p_0=\rho v\omega s_0=B k s_0$ Step 1: $p_0=\rho v\omega s_0$ where $s_0$ is displacement amplitude. Step 2: $\omega=2\pi\times1000=6283$ rad/s. Step 3: $s_0=p
Given Information
- Fluid density $\rho$, velocities, cross-sections, and heights as given
- Atmospheric pressure $P_0 = 1.013\times10^5\,\text{Pa}$
- $g = 9.8\,\text{m/s}^2$
Physical Concepts & Formulas
Fluid statics is governed by Pascal’s Law and the hydrostatic pressure formula $P = P_0 + \rho g h$. Archimedes’ principle states that the buoyant force equals the weight of fluid displaced: $F_b = \rho_f V g$. Fluid dynamics for ideal (incompressible, non-viscous, steady) flow uses two key results: the continuity equation $A_1 v_1 = A_2 v_2$ (mass conservation) and Bernoulli’s equation $P + \frac{1}{2}\rho v^2 + \rho g h = \text{const}$ (energy conservation per unit volume).
- $P = P_0 + \rho g h$ — hydrostatic pressure
- $F_b = \rho_f V g$ — Archimedes buoyancy
- $A_1 v_1 = A_2 v_2$ — continuity equation
- $P + \tfrac{1}{2}\rho v^2 + \rho g h = \text{const}$ — Bernoulli’s equation
- $v_{\text{efflux}} = \sqrt{2gh}$ — Torricelli’s theorem
Step-by-Step Solution
Step 1 — Identify the situation: Static (use $P = P_0+\rho gh$ and Archimedes) or dynamic (use continuity + Bernoulli).
Step 2 — Apply Bernoulli between two points at the same streamline:
$$P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2$$
Step 3 — Use continuity to relate $v_1$ and $v_2$: $v_2 = v_1 A_1/A_2$.
Step 4 — Solve for the unknown (pressure, velocity, or flow rate).
Worked Calculation
Substituting all values with units:
Torricelli: Tank depth $h = 2\,\text{m}$, hole at bottom:
$$v = \sqrt{2gh} = \sqrt{2\times9.8\times2} = \sqrt{39.2} \approx 6.26\,\text{m/s}$$
Answer
$$\boxed{v_{\text{efflux}} = \sqrt{2gh}}$$
Physical Interpretation
6.26 m/s is the speed at which water exits a tank with a 2 m head. This equals the speed a ball would have after falling freely 2 m — Torricelli’s theorem is essentially Bernoulli applied to free fall. As the water level drops, the efflux speed decreases; refilling to maintain constant head is the principle behind constant-head reservoirs in ancient water clocks (clepsydras).
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