Problem 6.46 — Davisson-Germer Electron Diffraction

Problem Statement

Solve the oscillation/wave problem: Electrons accelerated through $V = 54$ V diffract from Ni crystal at $\theta = 50°$. Find the interplanar spacing. $$\lambda = h/\sqrt{2m_eeV} = 6.626\times10^{-34}/\sqrt{2\times9.109\times10^{-31}\times54\times1.6\times10^{-19}} = 1.67 \text{ Å}$$ Bragg condition with glancing geometry: $d = \lambd

Given Information

  • All quantities, constants, and constraints stated in the problem above
  • Physical constants used as needed (see Concepts section)

Physical Concepts & Formulas

This problem draws on fundamental physical principles. The key is to identify which conservation law or field equation governs the system, then apply it systematically. Dimensional analysis can always be used to verify that the final answer has the correct units. Working from first principles — rather than memorising formulas — builds deeper understanding and allows tackling novel problems.

  • Identify the relevant physical law (Newton’s laws, conservation of energy/momentum, Maxwell’s equations, etc.)
  • State the mathematical form of that law as it applies here
  • Check dimensions at every step: both sides of an equation must have the same units

Step-by-Step Solution

Problem Statement

Solve the oscillation/wave problem: Electrons accelerated through $V = 54$ V diffract from Ni crystal at $\theta = 50°$. Find the interplanar spacing. $$\lambda = h/\sqrt{2m_eeV} = 6.626\times10^{-34}/\sqrt{2\times9.109\times10^{-31}\times54\times1.6\times10^{-19}} = 1.67 \text{ Å}$$ Bragg condition with glancing geometry: $d = \lambd

Given Information

  • Mass $m$ and spring constant $k$ (or equivalent), or wave parameters
  • Initial conditions (amplitude $A$, phase $\phi$) as given

Physical Concepts & Formulas

Simple harmonic motion arises whenever a restoring force is proportional to displacement: $F = -kx$. Newton’s second law then gives $\ddot{x} = -(k/m)x = -\omega_0^2 x$, whose solution is $x(t) = A\cos(\omega_0 t + \phi)$. The total mechanical energy $E = \frac{1}{2}kA^2$ is constant for ideal SHM. In waves, the same equation appears but in space-time: $\partial^2 y/\partial t^2 = v^2\,\partial^2 y/\partial x^2$.

  • $\omega_0 = \sqrt{k/m}$ — angular frequency
  • $T = 2\pi/\omega_0 = 2\pi\sqrt{m/k}$ — period
  • $x(t) = A\cos(\omega_0 t + \phi)$ — general SHM solution
  • $E = \tfrac{1}{2}kA^2$ — total mechanical energy
  • $v = f\lambda$ — wave speed

Step-by-Step Solution

Step 1 — Identify the restoring force and write the equation of motion.

Step 2 — Find $\omega_0$: $\omega_0 = \sqrt{k/m}$

Step 3 — Apply initial conditions to find $A$ and $\phi$.

Step 4 — Compute quantities asked (period, frequency, max velocity $v_{max}=A\omega_0$, max acceleration $a_{max}=A\omega_0^2$).

Worked Calculation

Substituting all values with units:

$$T = 2\pi\sqrt{\frac{m}{k}}\quad,\quad v_{\max} = A\omega_0 = A\sqrt{\frac{k}{m}}$$

Answer

$$\boxed{T = 2\pi\sqrt{m/k}}$$

Physical Interpretation

The period of a spring-mass oscillator depends only on $m$ and $k$ — not on the amplitude. This isochronous property is what made pendulum clocks reliable for centuries: large and small swings take the same time (for small angles).

Worked Calculation

Substituting all given numerical values with their units into the derived formula:

$$\text{Numerical result} = \text{given expression substituted with values}$$

Answer

$$\boxed{\boxed{T = 2\pi\sqrt{m/k}}}$$

Physical Interpretation

The answer should be checked for dimensional consistency and physical reasonableness: is the magnitude in the expected range for this type of problem? Does the answer change in the correct direction when parameters are varied (e.g., increasing mass should increase momentum, increasing distance should decrease field strength)? These sanity checks are as important as the calculation itself.


Comments

Leave a Reply

Your email address will not be published. Required fields are marked *