Problem Statement
Two point masses m₁ and m₂ are separated by distance d. Find the point on the line joining them where the gravitational field is zero.
Given
m₁, m₂, separation d. Field zero at distance x from m₁.
Concepts & Formulas
Fields from both masses cancel: Gm₁/x² = Gm₂/(d−x)².
Step-by-Step Solution
Step 1: At distance x from m₁: g₁ = Gm₁/x² (toward m₁) and g₂ = Gm₂/(d−x)² (toward m₂).
Step 2: Set g₁ = g₂: m₁/x² = m₂/(d−x)².
Step 3: √(m₁)/x = √(m₂)/(d−x) → x·√m₂ + x·√m₁ = d·√m₂… wait: (d−x)/x = √(m₂/m₁) → d/x = 1 + √(m₂/m₁) → x = d/(1+√(m₂/m₁)) = d√m₁/(√m₁+√m₂).
Worked Calculation
x = d√m₁/(√m₁ + √m₂) from m₁.
Boxed Answer
x = d√m₁/(√m₁ + √m₂)
Physical Interpretation
The null point lies closer to the lighter mass — it takes more distance to weaken the stronger field of the heavier body to the same level.
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