Problem Statement
A particle moves in the xy-plane. Its position is r = (at, bt²) where a and b are constants. Find the angular momentum about the origin.
Given
r(t) = (at, bt²). m = mass.
Concepts & Formulas
L = m(r × v). v = dr/dt = (a, 2bt). L_z = m(x·vy − y·vx).
Step-by-Step Solution
Step 1: x = at, y = bt², vx = a, vy = 2bt.
Step 2: L_z = m(x·vy − y·vx) = m(at·2bt − bt²·a) = m(2abt² − abt²) = mabt².
Step 3: dL_z/dt = 2mabt = torque.
Worked Calculation
L_z = mabt².
Boxed Answer
L_z = mabt²
Physical Interpretation
The angular momentum grows with time, confirming a non-zero torque acts — the trajectory curves under a force with a moment about the origin.
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