Problem Statement
A body of mass m₁ moving with velocity v₁ collides head-on with a stationary body of mass m₂. Find the velocity of each body after a perfectly elastic collision.
Given
m₁, v₁ (initial), m₂ at rest. Elastic collision.
Concepts & Formulas
Conservation of momentum: m₁v₁ = m₁v₁’ + m₂v₂’. Conservation of KE: ½m₁v₁² = ½m₁v₁’² + ½m₂v₂’². Elastic collision formulas apply.
Step-by-Step Solution
Step 1: v₁’ = v₁(m₁−m₂)/(m₁+m₂).
Step 2: v₂’ = 2m₁v₁/(m₁+m₂).
Step 3: Check momentum: m₁v₁(m₁−m₂)/(m₁+m₂) + m₂·2m₁v₁/(m₁+m₂) = m₁v₁[(m₁−m₂+2m₂)/(m₁+m₂)] = m₁v₁ ✓.
Worked Calculation
v₁’ = v₁(m₁−m₂)/(m₁+m₂). v₂’ = 2m₁v₁/(m₁+m₂).
Boxed Answer
v₁' = v₁(m₁−m₂)/(m₁+m₂); v₂' = 2m₁v₁/(m₁+m₂)
Physical Interpretation
For equal masses (m₁=m₂), the first body stops and the second moves with v₁ — a classic billiard-ball result. For m₁≫m₂, the heavy body barely slows.
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